Program to print the reverse of a number and also display the sum of its digits

        First u have to understand the question and think how to get into the question. Here are a few steps to follow.

1. To get the digits of a number.
2. Adding each digit to a variable
3. Print that digit
4. Finally print the sum of digits.

                Generally, to get the digits of a number, we use divison( / ) or modulo (%) operator. I hope, by using this, one can get the digits of a number. Here is a code for the above question.

#include<iostream>

using namespace std;

int main()

{

         int a,b,c=0;

         cout<<"enter the number: ";    // print reverse of number

         cin>>a;

        cout<<"reverse number is : ";

         while(a!=0)

        {

                  b=a%10;

                  cout<<b;

                  a=a/10;

                  c=c+b;

        }

        cout<< "\nsum of digits is: "<< c; // sum of the digits of number

        return 0;

}

Output:

Code :

CLICK HERE

           For this code, if u give input as 7400 then the corresponding output will be 0047 , that is equal to 47. So now U try to print in this format.